Home
Class 11
PHYSICS
A ball is thrown up under gravity . Find...

A ball is thrown up under gravity . Find its velocity after 1.0 sec at a height of 10m

A

`5m//s^2`

B

`5m//sec`

C

10m/sec

D

15m/sec

Text Solution

Verified by Experts

The correct Answer is:
D

`h = ut - 1/2 g t^2`
`rArr 10= u - 1/2 xx 10`
`rArr u = 15m//s`
Promotional Banner

Similar Questions

Explore conceptually related problems

A ball is thrown vertically up with a certain velocity. It attains a height of 40m and comes back to the thrower. Then the (g=10m//s^(2))

A ball is thrown vertically up with a certain velocity. It attains a height of 40 m and comes back to the thrower. Then the : (g = 10 m//s^(2)) .

When a ball is thrown up vertically with velocity v_0 , it reaches a maximum height of h. If one wishes to triple the maximum height then the ball should be thrown with velocity

A ball is thrown up with a certain velocity so that it reaches a height 'h'. Find the ratio of the two different times of the ball reaching (h)/(3) in both the directions.

An open elevator is ascending with constant speed v=10m//s. A ball is thrown vertically up by a boy on the lift when he is at a height h=10m from the ground. The velocity of projection is v=30 m//s with respect to elevator. Find (a) the maximum height attained by the ball. (b) the time taken by the ball to meet the elevator again. (c) time taken by the ball to reach the ground after crossing the elevator.

A body falls freely under gravity and moves for n sec. Its velocity after n sec is "V" .The displacement of the body in the last 3 sec is

A ball is thrown from the ground with a velocity of 20sqrt3 m/s making an angle of 60^@ with the horizontal. The ball will be at a height of 40 m from the ground after a time t equal to (g=10 ms^(-2))

A particle is thrown vertically upward. Its velocity at half of the height is 10 m/s. Then the maximum height attained by it : - (g=10 m//s^2)