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A body A is thrown up vertically from th...

A body A is thrown up vertically from the ground with velocity `V_(0)` and another body B is simultaneously dropped from a height H. They meet simultaneously dropped from a height H. They meet at a height `(H)/(2)` if `V_(0)` is equal to

A

`sqrt(2gH)`

B

`sqrt(gH)`

C

`1/2 sqrt(gH)`

D

`sqrt((2g)/(H))`

Text Solution

Verified by Experts

The correct Answer is:
B
For body A, `u = V_0, a = -g , h = H/2`
`H/2 = V_0 t - 1/2 g t^2`
For Body B
`H/2 = 1/2 g t^2 rArr t = sqrt(H/g)`
`rArr H/2 = V_0 sqrt(H/g) - 1/2 g xx H/g`
`rArr v_0^2 xx H/g = H^2 rArr v_0 = sqrt(gH)`
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