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A rocket is fired vertically up from the...

A rocket is fired vertically up from the ground with a resultant vertical acceleration of `10 m//s^2.` The fuel is finished in 1 min and it continues to move up. (a) What is the maximum height reached? (b) Afte2r how much time from then will the maximum height be reached?(Take `g= 10 m//s^2`)

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The correct Answer is:
36
Height covered in 1 min .
`s_(1) = ut +1/2 "gt"^(2) = 0 + 1/2 xx 10 xx (60)^(2) = 18000 m `
Velocity attained after 1 min ,
` v = u+at = 0 +10 xx 60 = 600 ms^(-1)`
After the fuel is finished , `u = 600 ms^(-1) , v= 0`
`v^(2) - u^(2) = 2gs `
`rArr 0 - (600)^(2) =2 xx (-9.8) xxs_(2)`
`rArr s_(2) = ((600)^(2))/(2xx9.8) = 18367.3 m `
Maximum height reached
`s_(1) +s_(2) = 36367.2 m `~=` 36.4 km .
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