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Block B lying on a table weighs w. The c...

Block B lying on a table weighs w. The coefficient of static friction between the block and the table is mu. Assume that the cord between B and the knot is horizontal. The maximum weight of the block A for which the system will be stationary is

A

`(W tan theta)/(mu)`

B

`mu W tan theta`

C

`mu W sqrt(1 + tan^(2) theta)`

D

`mu W sin theta`

Text Solution

Verified by Experts

The correct Answer is:
B
`T sin theta = W_(A) , T cos theta = mu W`
`therefore W_(A) = mu W tan theta`
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