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A car is moving along a straight horizon...

A car is moving along a straight horizontal road with a speed `v_(0)` . If the coefficient of friction between the tyres and the road is `mu` , the shortest distance in which the car can be stopped is

A

`(v_(0)^(2))/(2 mu g)`

B

`(v_(0))/(mu g)`

C

`((v_(0))/(mu g))^(2)`

D

`(v_(0))/(mu)`

Text Solution

Verified by Experts

The correct Answer is:
A
Retarding force = ma = `mu N = mu mg`
`implies a = mu g`
Stopping distance (S) = `(u^(2))/(2a) = (v_(0)^(2))/(2 mu g)`
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