Home
Class 11
PHYSICS
A body moves along a circular path of ra...

A body moves along a circular path of radius 10m and the coefficient of friction is 0.5.What should be its angular speed `(in rad s^(-1))`, if is not to slip from the surface ? `(Given,g =9.8ms^(-2))`

A

5

B

10

C

`0.1`

D

`0.7`

Text Solution

Verified by Experts

The correct Answer is:
D

`omega = sqrt((mu g)/( r))`
`omega = sqrt((0.5 xx 10)/(10)) = 0.7` rad/sec
Promotional Banner

Similar Questions

Explore conceptually related problems

A body moves along circular path of radius 50 m and the coefficient of friction is 0.4. What should be its angular velocity is rad//s if it is not to slip from the surface? (g=9.8 m//s^2 )

An electron moves along a circular path of radius 10 cm. If the centripetal acceleration is 4xx10^(11) m//s^(2) , then its linear speed is

A body moves along a circular path of radius 5m . The coefficient of friction between the surface of the path and the body is 0.5 . The angular velocity in rad//s with which the body should move so that it does not leave the path is (g-10m//s^(-2))

A particle moves in a circular path of radius 0.5 m with a linear speed of 2 ms^(-1) ,its angular speed is

If a particle of mass 1 gm is moving along a circular path of radius 1 m with a velocity of 1 m/s, then the its angular momentum is

Speed of an object moving in cirular path of radius 10 m with angular speed 2 rad/s is

A particle is moving along a circle of radius 3 m .If its centripetal acceleration is 3ms^(-2) , its angular velocity in rad s^(-1) is

A particle of mass 2 kg is moving along a circular path of radius 1 m. If its angular speed is 2pi" rad s"^(-1) , the centripetal force on it is