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A body is sliding down an inclined plan...

A body is sliding down an inclined plane having coefficient of friction 0.5 .If the normal reaction is 4 times that of the resultant downward force along the incline, find the angle between the inclined plane and the horizontal.

A

`15^(@)`

B

`30^(@)`

C

`45^(@)`

D

`60^(@)`

Text Solution

Verified by Experts

The correct Answer is:
C
Resultant downward force = `mg (sin theta - mu cos theta)`
N = mg `cos theta`
Since , mg `cos theta = 2 mg (sin theta - mu cos theta)`
`implies 1 = 2 tan theta - 2 mu implies tan theta =1`
`implies theta = 45^(@)`
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