A rod `AB` of length `2m` is hinging at point A and its other end B is attached to a platform on which a point of mass m is kept. Rod rotates about point `A` maintain angle `theta = 30^(@)` with the vertical in such a way that platform remain horizontal and revolves on the horizontal circular path. If the coefficient of static friction between the block and platform is `mu = 0.1` then find the maximum angular velocity in rad`s^(-1)` of rod so that the block does not slip on the platform `(g = 10 ms^(-2))`

Answer

1

Explanation

`N=mg, muN=mromega^(2)`

`mumg=m2sinthetaomega^(2)`
`impliesomega=sqrt((mug)/(2sintheta))=sqrt((0.1xx10)/(2xxsin30))=1rads^(-1)`