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A block is placed on an inclined plane a...

A block is placed on an inclined plane as shown in figure. What must be the friction force between block and inclined if the block is not to slide along the inclined when the incline is accelerating to the right at `3 m//s^(2) ( sin 37^(@) = (3)/(5))`? `(Take g = 10 m//s^(2))`

Text Solution

Verified by Experts

The correct Answer is:
90

From figure,
`mu mg cos37^(@)=mgsin37^(@)-macos37^(@)`
`implies mu mg xx(4)/(5)=(gxx3)/(5)-(3xx4)/(5)`
`implies40 mu g=3g-12=18 :. Mu=(9)/(20)=0.75`
And frictional force
`F=mgxx(3)/(5)-mxx(3g)/(10)xx(4)/(5)`
`F=mg((3)/(5)-(6)/(25))=(9)/(25)mg`
`=(9)/(25)xx25xx10=90N`.
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