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The potential energy of a particle under...

The potential energy of a particle under a conservative force is given by `U ( x) = ( x^(2) -3x)` J. The equilibrium position of the particle is at

A

x = 1.5 m

B

x = 2m

C

x = 2.5 m

D

x = 3m

Text Solution

Verified by Experts

The correct Answer is:
A
`V(x) = (x^2 -3x)`
`F = -(dV)/(dx) =-(2x-3)`
For equilibrium position
`2x - 3 =0implies x =3/2 =1.5 m`
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