A positon dependent force ,F=8-4x+3x^(2)...

A positon dependent force ,`F=8-4x+3x^(2)N` acts on a small body of mass 2 kg and displaces it from x=0 to x=5 m. The work done in joule is

A

70

B

270

C

35

D

135

Verified by Experts

The correct Answer is:

D

`W=int_0^5 Fdx = int_0^5(7-2x +3x^2)dx`
`=[7x - x^2 + x^3]_(0)^(5) [35 - 25 + 125] = 135`

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