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A 0.5 kg ball is thrown up with an initi...

A 0.5 kg ball is thrown up with an initial speed 14 m/s and reaches a maximum height of 8.0 m . How much energy is dissipated by air drag acting on the ball during the ascent

A

19.6Joule

B

4.9 Joule

C

10 Joule

D

9.8 Joule

Text Solution

Verified by Experts

The correct Answer is:
D
`H_("max")=u^2/(2g) =((14)^2)/(2xx9.8)=10 m`
Energy difference =
`mg(H_("max")-8) =0.5 xx 9.8 xx 2 = 9.8J.`
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