Home
Class 11
PHYSICS
What is the velocity of the bob of a sim...

What is the velocity of the bob of a simple pendulum at its mean position, if it is able to rise to vertical height of 10 cm (take `g=9.8m//s^(2)`)

A

0.6 m/s

B

1.4 m/s

C

1.8 m/s

D

2.2 m/s

Text Solution

Verified by Experts

The correct Answer is:
B

mgh `=1/2 mv^2 implies v= sqrt(2gh)`
`= sqrt(2xx9.8 xx0.1) = 1.4 m//s`
Promotional Banner

Similar Questions

Explore conceptually related problems

Calculate the velocity of the bob of a simple pendulum at its mean position if it is able to rise to a vertical height of 10 cm. Take g=9.8 ms^(-2) .

The velocity of the bob of a simple pendulum in the mean position is v. If its amplitude is doubled, by keeping the same length, then its velocity in the mean position will be

The centre of gravity C.G. of the bob of a given simple pendulum is at position 'x' on earth. What is its new position on the surface of the moon?

A pendulum bob of mass m = 80 mg, carrying a charge of q=2xx10^(-8)C , is at rest in a horizontal, uniform electric field of E = 20,000 V/m. The tension T in the thread of the pendulum and the angle alpha it makes with vertical, is (take g=9.8m//s^(2) )

The bob of a pendulum is moving with a speed of 5 m/s while passing through mean position . Calculate its speed at the position when it makes an angle of 30^(@) with the vertical . The length of pendulum is 0.6 m / Use g = 10 m//s^(2)

A ball is moving to and fro about the lowest point A of a smooth hemispherical bowl. If it is able to rise up to a height of 20 cm on either side of A , its speed at A must be (Take = 10m//s , mass of the body 5 g )

The given figure shows the variation of the kinetic energy of a simple pendulum with its angular displacement (theta) from the vertical. Mass of the pendulum bob is m = 0.2 kg. Find the time period of the pendulum. Take g = 10 ms^(-2) .

Find the maximum height reached by a particle which is thrown vertically upwards with the velocity of 20 m//s (take g= 10 m//s^(2) ).