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300J of work is done in slinding a 2 kg ...

300J of work is done in slinding a 2 kg block up an inclined plane of height 10m. Taking g =`10m//s^(2)` , work done against friction is

A

100 J

B

200 J

C

300 J

D

Zero

Text Solution

Verified by Experts

The correct Answer is:
A
Work done against gravity = mgh =` 2 xx10 xx10 = 200 J`
Work done against friction = (Total work done – work done against gravity) = 300 - 200 = 100J.
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