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An engine pumps up 100 kg water through ...

An engine pumps up `100 kg` water through a height of `10 m` in `5 s`. If efficiency of the engine is `60%`. What is the power of the engine? `Take g = 10 ms^(2)`.

A

3.3 kW

B

0.33 kW

C

0.033 kW

D

33 kW

Text Solution

Verified by Experts

The correct Answer is:
A
`P = (100 xx10xx 10)/5 implies (mgh)/t implies P = 2kW`
`eta = ("Power output")/("Power input") implies 0.60 = (2xx10^3)/P_i`
`implies P_(i) = (2xx10^4)/6 = 3.33 kW`
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