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A particle of mass m moving with horizon...

A particle of mass `m` moving with horizontal speed `6 m//s` as shown in the figure. If `m lt lt M` then for one - dimensional elastic collision , the speed of lighter particle after collision will be

A

2m/sec in original direction

B

2 m/sec opposite to the origin

C

4 m/sec opposite to the original direction

D

4 m/sec in original direction

Text Solution

Verified by Experts

The correct Answer is:
A
`m_1 = m, u_1=6m//s, m_2 = M, u_2 =4m//s`
`v_1=((m_1-m_2)/(m_1+m_2))u_1=(2m_2u_2)/(m_1+m_2)=-u_1+2u_2`
`implies -6 + 8 = 2m//s " " [:. "As" m_1/m_2lt ltlt1]`
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