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Two sphere A and B of masses m(1) and m(...

Two sphere `A and B` of masses `m_(1) and m_(2)` respectivelly colides. A is at rest initally and `B` is moving with velocity `v` along x-axis. After collision `B` has a velocity `(v)/(2)` in a direction perpendicular to the original direction. The mass `A` moves after collision in the direction.

A

Same as that of B

B

Opposite to that of B

C

`theta = tan^(-1)(1// 2)` to the x-axis

D

`theta = tan^(-1)(-1// 2)` to the x-axis

Text Solution

Verified by Experts

The correct Answer is:
C
In x – direction
`m_2v=m_1v_x implies v_x = (m_2v)/m_1`
In y - direction
`m_2 xx v/2 = m_1v_y implies v_y = (m_2v)/(2m_1)`
`tan theta =v_y/v_x =1/2`
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