Home
Class 11
PHYSICS
A ball moving with velocity 2 ms^(-1) co...

A ball moving with velocity `2 ms^(-1)` collides head on with another stationary ball of double the mass. If the coefficient of restitution is `0.5`, then their velocities (in `ms^(-1)`) after collision will be

A

`0, 2`

B

`0, 1`

C

`1, 1`

D

`1, 0.5`

Text Solution

Verified by Experts

The correct Answer is:
B
`m_1 = m: u_1 = 2m//s , m_2 = 2m,u_2 = 0`
`v_1 =((m_1-em_2)/(m_1+m_2))u_1 =((m-0.5 xx2m)/(3m))xx2 = 0`
`v_2 =(m_1(1+e)u_1)/(m_1+m_2)=(mxx1.5 xx2)/(3m) = 1m//s`
Promotional Banner

Similar Questions

Explore conceptually related problems

A ball moving with velocity 2 ms^(-1) collides head on with another stationary ball of double the mass. If the coefficient of restitution is 0.5 , then their velocities (in ms^(-1) ) after colllision will be

A ball P is moving with a certain velocity , collides head-on with another ball Q of same mass is rest. The coefficient of restitution is 1/4, then ratio of velocity of P and Q just after the collision is

A body of mass m moving with a constant velocity collides head on with another stationary body of same mass if the coefficient of restitution between the bodies is (1)/(2) then ratio of velocities of two bodies after collision with be

A block of mas m moving at a velocity upsilon collides head on with another block of mass 2m at rest. If the coefficient of restitution is 1/2, find the velocities of te blocks after the collision.

The first ball of mass m moving with the velocity upsilon collides head on with the second ball of mass m at rest. If the coefficient of restitution is e , then the ratio of the velocities of the first and the second ball after the collision is

A ball of mass m moving with velocity v collides head-on which the second ball of mass m at rest. I the coefficient of restitution is e and velocity of first ball after collision is v_(1) and velocity of second ball after collision is v_(2) then