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A spring of spring constant 5 xx 10^(2) ...

A spring of spring constant `5 xx 10^(2) `Nm is streched initially by `5 cm` from the unstriched position . Then the work required to streach is further by another `5 cm` is

A

6.25 N-m

B

12.50 N-m

C

18.75 N-m

D

25.00 N-m

Text Solution

Verified by Experts

The correct Answer is:
C
`U= (1)/(2) k (x_(2)^(2)- x_(1)^(2)) = (1)/(2) xx 5 xx 10^(3) [10^(2)- 5^(2)] xx 10^(-4)`
`= (1)/(2) xx 5 xx 75 xx 10^(-1)= 18.75J`
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