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A particle is placed at the origin and a...

A particle is placed at the origin and a force F=Kx is acting on it (where k is a positive constant). If `U_((0))=0`, the graph of `U (x)` verses x will be (where U is the potential energy function.)

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Text Solution

Verified by Experts

The correct Answer is:
A
`U =- int Fdx= - int kx dx= - (kx^(2))/(2)`
at x= 0, U= 0
at `x= pm A, U= (-kA^(2))/(2)`
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