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A bullet of mass 10 g moving horizontall...

A bullet of mass 10 g moving horizontally with a velocity of `400ms^(-1)` strikes a wooden block of mass 2kg which is suspended by a light inextensible string of length 5 m. As a result, the centre of gravity of the block is found to rise a vertical distance of 10 cm. The speed of the bullet after it emerges out horizontally from the block will be

A

`160 ms^( -1)`

B

`100 ms^(-1)`

C

`80 ms^(-1)`

D

`120 ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
During the collision, apply momentum conservation (0.01) (400)+ 0= (2)v+ (0.01)v ...(i)
where `v= sqrt(2gh) = sqrt(2 xx 10 xx 0.1)= sqrt2`
from (i) `4= 2 xx sqrt2 + 0.01v`
solving v= 120m/sec
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