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A block moving horizontally on a smooth surface with a speed of 40 m/s splits into two parts with messes in the ratio of 1:2 If the smaller part moves at 60 m/s in the same direction , then fractional change in kinetic energy is :

A

`(1)/(3)`

B

`(2)/(3)`

C

`(1)/(4)`

D

`(1)/(8)`

Text Solution

Verified by Experts

The correct Answer is:
D


`m xx 40= (2)/(3) mv+ (m)/(3) xx 60`
120= 2v+60
v= 30m/s
Now `K_(i)= (1)/(2) xx m xx 40^(2)= 800m`
`K_(f)=(1)/(2) xx (2m)/(3) (0)^(2)+ (1)/(2) xx (m)/(3) xx (60)^(2)`
`=(1)/(6) {m(1800+3600)}= (m(5400))/(6)= 900m`
`(Delta KE)/(K_(i))= (900m- 800m)/(800m)= (1)/(8)`
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