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The depth d, at which the value of accel...

The depth `d`, at which the value of acceleration due to gravity becomes 1/n times the value at the surface is (R = radius of the earth)

A

`R/n`

B

`R((n-1)/n)`

C

`R/(n^2)`

D

`R(n/(n+1))`

Text Solution

Verified by Experts

The correct Answer is:
B
`g.=g(1-d/R)`
`rArrg/n=g(1-d/R)rArrd/R=1-1/h`
`rArrd=R((n-1)/n)`
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