Home
Class 11
PHYSICS
The height of the point vertically above...

The height of the point vertically above the earth's surface, at which acceleration due to gravity becomes 1% of its value at the surface is (Radius of the earth =R)

A

8R

B

9R

C

10R

D

20R

Text Solution

Verified by Experts

The correct Answer is:
B

`g.=g/((1+h/R)^2)rarr0.01g=g/((1+h/r)^2)`
`rArr0.1=R/(R+h)=h=(0.09)/(0.1)R=9R`
Promotional Banner

Similar Questions

Explore conceptually related problems

The height of the point vertically above the earth's surface, at which acceleration due to gravtiy becomes 1% of its value at the surface is (Radius of the earth =R)

The height vertically above's surface at which the acceleration due to gravity becomes 1% of its value at the suuface is

The depth d , at which the value of acceleration due to gravity becomes 1/n times the value at the surface is (R = radius of the earth)

At a height equal to earth's radius, above the earth's surface, the acceleration due to gravity is

The depth at which the value of acceleration due to gravity is 1/n times the value at the surface, is (R=radius of the earth)

If R is the radius of the earth , the height from its surface at which the acceleration due to gravity is 9% of its value at the surface is

How much below the surface of the earth does the acceleration due to gravity become 1% of its value at the earth's surface ? Radius of the earth=6400 km.

At what height above the earth's surface the acceleration due to gravity will be 1/9 th of its value at the earth’s surface? Radius of earth is 6400 km.