Home
Class 11
PHYSICS
The imaginary angular velocity of the ea...

The imaginary angular velocity of the earth for which the effective acceleration due to gravity at the equator shall be zero is equal to
[Take g `= 10 m//s^(2)` for the acceleration due to gravity if the earth were at rest and radius of earth equal to 6400 km.]

A

`1.25xx10^(-3)rad//s`

B

`2.50xx10^(-3)rad//s`

C

`3.75xx10^(-3)rad//s`

D

`5.0xx10^(-3)rad//s`

Text Solution

Verified by Experts

The correct Answer is:
A
`g.=g-omega^2Rcos^2lamda=0`
`omega^2R=g`
`rArromega=sqrt((9.8)/(6400xx10^3))`
`omega=1.25xx10^(-3)` rad/s
Promotional Banner

Similar Questions

Explore conceptually related problems

Find the imaginary angular velocity of the earth for which the effective acceleration due to gravity at the equator shall be zero. (take g = 10 m//s^(2) for the acceleration due to gravity, if the earth were at rest and radius of earth equal to 6400 km and phi = 60^(@) )

Acceleration due to gravity of earth

Acceleration due to gravity at the centre of the earth is :-

Let g be the acceleration due to gravity on the earth's surface.

The angular velocity of the earth with which it has to rotate so that the acceleration due to gravity on 60^@ latitude becomes zero is

What is the value of the acceleration due to gravity at a height equal to radius of earth?

At the centre of earth the acceleration due to gravity is