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A geostationary satellite is orbiting th...

A geostationary satellite is orbiting the earth at a height of `5R` above the surface of the earth, `2R` being the radius of the earth. The time period of another satellite in hours at a height of `2R` form the surface of the earth is

A

5

B

10

C

`6sqrt2`

D

`(6)/(sqrt2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`Tpropr^(3/2)rArr(T_1)/(T_2)=((6R)/(3R))^(3/2)`
`rArrT_2=6sqrt2`. [as `T_1=24` hrs]
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