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Given radius of Earth 'R' and length of...

Given radius of Earth 'R' and length of a day 'T' the height of a geostationary satellite is [G- Gravitational constant. M - Mass of Earth]

A

`((4pi^2GM)/(T^2))^(1//3)`

B

`((4piGM)/(R^2))^(1//3)-R`

C

`((GMT^2)/(4pi^2))^(1//3)-R`

D

`((GMT^2)/(4pi^2))^(1//3)+R`

Text Solution

Verified by Experts

The correct Answer is:
C
`T=2pisqrt(((R+h)^3)/(GM))rArrT^2=(4pi^2)/(GM)(R+h)^3`
`rArrR+h=((GMT^2)/(4pi^2))^(1/3)rArrh=((GMT^2)/(4pi^2))^(1/3)-R`
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