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The figure shows elliptical orbit of a p...


The figure shows elliptical orbit of a planet m about the sun S. the shaded area SCD is twice the shaded area SAB. If `t_(1)` be the time for the planet to move from C to D and `t_(2)` is the time to move from A to B, then:

A

`t_1 gt t_2`

B

`t_1=4t_2`

C

`t_1=2t_2`

D

`t_1=t_2`

Text Solution

Verified by Experts

The correct Answer is:
C
Since, ariel velocity is constant
`(DeltaA)/(Deltat)=L/(2m)rArrDeltaApropt`
`rArr(DeltaA_(SCD))/(DeltaA_(SAB))=(t_1)/(t_2)rArr(2A)/A=(t_1)/(t_2)rArrt_1=2t_2`
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