Two particles of equal mass go around a circle of radius R under the action of their mutual gravitational attraction. Find the speed of each particle.

Options

A. `v=(1)/(2R)sqrt((1)/(Gm))`
B. `v=sqrt((Gm)/(2R))`
C. `v=(1)/(2)sqrt((Gm)/(R))`
D. `v=sqrt((4Gm)/(R))`

Answer

C

Explanation

`(Gm^(2))/((2R)^(2))=(mv^(2))/(R)impliesv=sqrt((Gm)/(4R))=(1)/(2)sqrt((Gm)/(R))`