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The time period of a geostationary sat...

The time period of a geostationary satellite at a height 36000 km is 24 h. A spy satellite orbits very close to earth surface (R=6400 km ) what will be its time period ?

A

4 hrs

B

1 hrs

C

2 hrs

D

1.5 hrs

Text Solution

Verified by Experts

The correct Answer is:
C
Since, `T^(2)propr^(3)`
`(T^(2))/((24)^(2))=((6400)/(36000))^(2)`
`impliesT=1.79hrs~~2hrs`.
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