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If the angular momentum of a planet of m...

If the angular momentum of a planet of mass m, moving around the Sun in a circular orbit is L, about the center of the Sun, its areal velocity is :

A

`(2L)/(m)`

B

`(4L)/(m)`

C

`(L)/(2m)`

D

`(L)/(m)`

Text Solution

Verified by Experts

The correct Answer is:
C

`dA=(1)/(2)r^(2)d theta`
`(dA)/(dt)=(1)/(2)r^(2)(d theta)/(dt)`
`(dA)/(dt)=(1)/(2)r^(2)omega=(L)/(2m)` since `L=mr^(2)omega`
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