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A drop of mercury of radius 2 mm is spli...

A drop of mercury of radius 2 mm is split into 8 identical droplets. Find the increase in surface energy. Surface tension of mercury `=0.465Jm^-2`

A

`23.4 mu J`

B

`18.5 muJ`

C

`26.8 muJ`

D

`16.8 muJ`

Text Solution

Verified by Experts

The correct Answer is:
A
`W=4piTR^2 (n^(1//3)-1)`
`=4pi xx0.465xx(2xx10^(-3))(8^(1//3)-1)`
`=23.4 muJ`
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