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The excess pressure inside a soap bubble...

The excess pressure inside a soap bubble is twice the excess pressurre inside a second soap bubble. The volume of the first bubble is n times the volume of the second where n is

A

8

B

4

C

2

D

`0.125`

Text Solution

Verified by Experts

The correct Answer is:
D
`(DeltaP_1)/(DeltaP_2)=R_2/R_1implies 2= R_2/R_1impliesR_1/R_2=1/2`
`V_1 =nV_2`
`implies 4/3 piR_(1)^(3) = n (4)/3 piR_2^3 implies n =1/8 = 0.125`
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