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The rise in the water level in a capilla...

The rise in the water level in a capillary tube of radius 0.07 cm when dipped vertically in a beaker containing water of surface tension `0.07 N m^(-1)` is (g = `10 m s^(-2)`)

A

2 cm

B

4 cm

C

1.5 cm

D

3 cm

Text Solution

Verified by Experts

The correct Answer is:
A

`h= (2sigma cos theta)/(rhorg)=(2xx0.07 xx1)/((0.07 xx10^(-2))(10^3)(10))`
[ Angle of contact `theta_("water")=0^@` ]
`= 2xx10^(-2)m = 2cm`
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