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Work done in increasing the size of a so...

Work done in increasing the size of a soap bubble from a radius of `3 cm` to `5 cm` is nearly. (surface tension of soap solution `= 0.3 Nm^(-1))`

A

`4pi ` mJ

B

`0.2pi ` mJ

C

`2pi ` mJ

D

`0.4pi ` mJ

Text Solution

Verified by Experts

The correct Answer is:
D
`W=8pi//T(R_2^2-R_1^2)`
`=8pi xx0.03 (5^2 -3^2) xx 10^(-4) =0.4 pi mJ`
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