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The ratio of surface tensions of mercury...

The ratio of surface tensions of mercury and water is given to be 7.5 while the ratio of their densities is 13.6. Their contact angles, with glass, are close to 135° and 0°, respectively. It is observed that mercury gets depressed by an amount h in a capillary tube of radius `r_(1)` while water rises the same amount h in a capillary tube of radius `r_(2)`. The ratio, `(r_(1)//r_(2))` , is then close to

A

`4/5`

B

`3/5`

C

`2/5`

D

`2/3`

Text Solution

Verified by Experts

The correct Answer is:
C
`|h_(Hg)|=|h_("water")|`
`(2S_(Hg)cos theta_(Hg))/(rho_(Hg)R_(Hg)g)=(2S_(w)cos theta_w)/(rho_wR_Wg)`
`(R_(Hg))/(R_W)=(rho_W)/(rho_(Hg))(S_(Hg))/S_W(cos theta_(Hg))/(cos theta_W)`
`=1/13.6 xx7.5 xx 1/sqrt2`
`R_(Hg)/(R_W)=0.4 =2/5`
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