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Three liquids of equal masses are taken ...

Three liquids of equal masses are taken in three identical cubical vessels A,B and C. Their densities are `rho_(A),rho_(B)` and `rho_(C)` respectively but `rho_(A)ltrho_(B)ltrho_(C)`. The force exerted by the liquid on the base of the cubical vessel is

A

Maximum in vessel C

B

Minimum in vessel C

C

The same in all the vessels

D

Maximum in vessel A

Text Solution

Verified by Experts

The correct Answer is:
C
`P=rho gh`
`rho=("Mass")/("Volume")=(m)/(Ah) implies h= (m)/(rho xx A)`
`:. P=rho g xx (m)/(rho xx A)=(mg)/(A)`
Force `F=P xx A= (mg)/(A) xx A = mg`
`m_A =m_B=m_C implies F_A = F_B=F_C`
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