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The force acting on a window of area 50c...

The force acting on a window of area `50cm xx 50cm` of a submarine at a depth of `2000 m` in an ocean, the interior of which is maintained at sea level atmospheric pressure is (Density of sea water = `10^(3)kgm^(-3)`, `g = 10ms^(-2)`)

A

`10^6 N`

B

`5xx10^5 N`

C

`25xx10^6` N

D

`5xx10^6 N`

Text Solution

Verified by Experts

The correct Answer is:
D
Pressure outside the submarine = `P = P_a+rho gh` [`P_a rarr` atm]
Pressure inside the submarine = `P_a`
Net pressure acting on window (Gauge pressure)
`P_g=P-P_a=rho gh=10^3 xx10xx2000`
Force (F) = `P_g xx A=2xx10^7 xx 2500xx10^(-4)`
= `5xx10^6` N.
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