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The velocity of water in river is 180 km...

The velocity of water in river is 180 km `h^(-1)` near the surface .If the river is 5 m deep, then the shearing stress between the surface layer and the bottom layer is ( coefficient of viscosity of water `eta =10^(-3)` Pa s)

A

`0.6xx10^(-3) Nm^(-2)`

B

`0.8xx10^(-3) Nm^(-2)`

C

`0.5xx10^(-3) Nm^(-2)`

D

`10^(-3) Nm^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
C
v= 5 m/s, Strain rate =`v/l`
Coefficient of `eta = ("Shearing stress")/("Strain rate")`
Shearing stress = `eta xx` Strain rate
`= 10^(-3) xx (5)/(10) =0.5xx10^(-3) N//m^2`.
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