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The water flows form a tap of diameter 1...

The water flows form a tap of diameter `1.25` cm with a rate of `5xx10^(-5) m^(3) s^(-1).` The density and coefficient of viscosity of water are `10^(3)kg m ^(-3) and 10^(-3)` Pa. s respectively. The flow of water is

A

Steady with Reynolds number 5100

B

Turbulent with Reynolds number 5100

C

Steady with Reynolds number 3900

D

Turbulent with Reynolds number 3900

Text Solution

Verified by Experts

The correct Answer is:
B
`N_R=(v rho D)/(eta)" "`…(i)
Now, `Q=(pi D^2)/(4)xx v implies v=(4Q)/(pi D^2)" "`…(ii)
By eq. (i) and (ii) `N_R=(4Q rho)/(pi D eta)`
`implies (4xx5xx10^(-5)xx10^(3))/(3.14xx1.25xx10^(-2)xx10^(-3))=5095 ~~ 5100` (Approx.)
`N_R gt 3000` (turbulent)
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