Water flow through a horizontal pipe whose internal diameter is `2.0 cm` at a speed of `1.0 ms^(-1)` What should be the diameter of the nozzle, If the water is to emerge at a speed of `4.0ms^(-1)`?

Answer

1

Explanation

Here `d_(1) = 2 cm = 0.02 m, v_(1) = 1 ms ^(-1) , v_(2) = 4 ms^(-1) d_(2) = ?`
Using equation of continuity
`a_(1) v_(1) = a_(2) v_(2)`
or ` ( pi d_(1)^(2))/( 4) xx v_(1) = ( pi d_(2)^(2)) /( 4) xx v_(2)`
or `d_(2)^(2) = (v_(1))/( v_(2)) xx d_(1)^(2) = (1)/(4) xx (0.02)^(2) = (0.01) ^(2)`
or ` d_(2) = 0.01 m = 1.0 cm`