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A submarine experiences a pressure of 5....

A submarine experiences a pressure of `5.05xx10^(6)Pa` at a depth of `d_(1)` in a sea When it goes futher to a depth of `d_(2)`. It experiences a pressure of `8.08xx10^(6)Pa`. The `d_(2)-d_(1)` is approximately (density of water `=10^(3)kg//m^(3)` and acceleration due to gravity `=10ms^(-2))`

A

400m

B

500m

C

600 m

D

300 m

Text Solution

Verified by Experts

The correct Answer is:
D
`rho g (d_(2) - d_(1)) = P_(2) - P_(1) rArr d_(2) - d_(1) =303 m `
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