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A cubical block of side 0.5 m floats on ...

A cubical block of side 0.5 m floats on water with 30% of its volume under water. What is the maximum weight that can be put on the block without fully submerging it under water?
[Take, density of water `= 10^(3) kg//m^(3)`]

A

87.5 kg

B

46.3 kg

C

30.1 kg

D

65.4 kg

Text Solution

Verified by Experts

The correct Answer is:
A
Initially, B mg
` rho (3)/( 10) Vg= mg ` . . . (i)
`rArr (1000 kg//m^(3)) (3)/( 10) (0.5 m) ^(3) = m`
m = 37.5 kg
Finally, `rho v g = (m + M)g ` . . . (ii)
from equation (i) and (ii)
`((m + M) g)/( mg) = (rho V g)/(rho(3)/(10) Vg)`
`1 + (M)/(m) = (10)/(3)`
`(M)/( m) = (7)/(3)`
`M = (7)/(3) (37.5) kg = 87 . 3 kg`
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