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A drop of Volume V is pressed between th...

A drop of Volume `V` is pressed between the two glass plates so as to spread to an area of `A`. If `T` is the surface tension, the normal force required to separate the glass plates is

A

`r = sqrt(( T)/((d + rho ) g))`

B

`r = sqrt((3 T)/((2d -rho ) g))`

C

`r = sqrt(( T)/((d -rho ) g))`

D

`r = sqrt(( 2T)/(3(d +rho ) g))`

Text Solution

Verified by Experts

The correct Answer is:
B

`dVg = rho ((V)/(2)) g + T (2 pi r)`
`rArr d. (4)/(3) pi r^(3) g = rho (2)/(3) pi r^(3) g + 2 pi r T `
`rarr (2)/( 3) r^(2) g ( 2 d- rho) = 2T rArr r = sqrt((3T)/((2 d - rho) g))`
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