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If gamma is the ratio of specific heat...

If ` gamma ` is the ratio of specific heats and R is the universal gas constant, then the molar specific heat at constant volume `C_V ` is given by

A

`(R)/(y-1)`

B

`(YR)/(Y-1)`

C

`YR`

D

`((Y-1)R)/(Y)`

Text Solution

Verified by Experts

The correct Answer is:
A
`(C_p)/(C_v) = gamma rArr C_p = gamma C_(v)`
and `C_(p) = C_(v) = R rArr C_(v) = C_(p) - R`
`rArr C_(v) + R = C_(p) rArr C_(v) + R = gamma C_(v)`
`rArr C_v = (R)/(gamma - 1)`
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