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At 40^(@)C a brass wire of 1mm radius is...

At `40^(@)C` a brass wire of 1mm radius is hung from the ceiling. A small mass, M is hung from the free end of the wire. When the wire is cooled down from` 40^(@)C` to `20^(@)C` it regains its original length of 0.2 m the value of M is close to (coefficient of linear expansion and young's modulus of brass are `10^(-5)//.^(@)C` and `10^(11)//N//m^(2)` respectively `g=10ms^(-2))`

A

6.28 Kg

B

1.5 Kg

C

0.9 Kg

D

0.5 Kg

Text Solution

Verified by Experts

The correct Answer is:
A

`(Mgl)/(A Delta l)=Y`
`therefore Delta l_("mechanical")=(Mg l)/(AY)`
`Delta l_("thermal")=l alpha Delta T = l alpha xx 20`
`(Mgl)/(AY)=20 alpha l`
`M=(20xx10^(-5)xx pi xx 1 xx 10^(-6)xx10^(11))/(10)=6.28` Kg
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