A liquid of mass `M` and specific heat `S` is at a temperature `2T`. Another liquid of thermal capacity `1.5 times` the first liquid at a temperature `(T)/(3)` is added to it. The resultant temperature of the mixture will be

Options

A. `4/3t`
B. t
C. `t/2`
D. `2/3`t

Answer

B

Explanation

`theta_(mix)=(m_1c_1 theta_1+m_2c_2theta_2)/(m_1c_1+m_2c_2)=(ms(2t)+1.5(ms)xxt/3)/(ms+1.5 (ms))=t`
Aliter :
`MS (2t-T)=Mxx 1.5 S(T-t/3)`
`implies 2t-T=1.5T-t/2 implies (5t)/(2)=2.5T implies T=t`