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Steam at 100^(@)C is passed into 1.1 kg ...

Steam at `100^(@)C` is passed into `1.1 kg` of water contained in a calorimeter of water equivalent `0.02kg` at `15^(@)C` till the temperature of the calorimeter and its content rises to `80^(@)C`. What is the mass of steam condensed? Latent heat of steam = `536 cal//g`.

A

`0.130`

B

`0.065`

C

`0.260`

D

`0.135`

Text Solution

Verified by Experts

The correct Answer is:
A
Heat lost = Heat gain
`implies m xx 1(100-80)+mxx540=(1.1+0.02)xx(80-15)`
`implies m xx 560 =1.12 xx 65`
`m=(1.12 xx 65)/(560)=0.13` kg.
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