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A bullet of mass 5 g travelling with a s...

A bullet of mass 5 g travelling with a speed of 210 m/s, strikes a fixed wooden target. One half of its kinetic energy is converted into heat in the bullt while the other half is coverted into heat in the wood. The rise of temperature of the bullet if the specific heat of its meterial is 0.030 cal/`(g - ""^@C) (1 cal = 4.2 xx 10^7" ergs")` close to :

A

`87.5^@C`

B

`83.3^@C`

C

`119.2^@C`

D

`38.4^@C`

Text Solution

Verified by Experts

The correct Answer is:
A
As per given condition
`1/2 xx 1/2 mv^2=(msDeltaT)_("bullet")`
`DeltaT=(v^2)/(4s)`
`=(210 xx 210)/(4.4.2 xx 0.3 xx 1000)=87.5^@C`
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