In the circuit shown in figure `C_(1) =C_(2) = 2muF`. Then charge stored in

In the circuit shown in figure, C=6muF The charge stored in capacitor of capacity C is

In the circuit shown in figure C_(1) = 2 C_(2) . Capacitance C_(1) is charged to a potential of V. The current in the circuit just after the switch S is closed is

In the circuit shown in figure C_(1) = 2 C_(2) . Capacitance C_(1) is charged to a potential of V. The current in the circuit just after the switch S is closed is

In the circuit shown in, C=6 muF . The charge stored in the capacitor of capacity C is .

In the circuit shown in figure. Find The charge stored in each capcicitor.

In the ciruit shown in, C=6 muF . The charge stored in the capacitor of capacity C is .

In the ciruit shown in, C=6 muF . The charge stored in the capacitor of capacity C is .

In the circuit shown, C_(1)=C_(2)=2 muF . Capacitor C_(1) is charged to 50 V and C_(1) is charge to 20 V . After charging they are connected as shown. When S_(1), S_(2) , and S_(3) , are clsosed, .

In the circuit shown, C_(1)=C_(2)=2 muF . Capacitor C_(1) is charged to 50 V and C_(1) is charge to 20 V . After charging they are connected as shown. When S_(1), S_(2) , and S_(3) , are clsosed, .

In the circuit shown in figure, find the charge stored in each capacitance